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Message boards :
General discussion :
Prime Score
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 robish Volunteer moderator
Volunteer tester
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Joined: 7 Jan 12
Posts: 2136
ID: 126266
Credit: 6,782,465,899
RAC: 2,761,228
                             
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The scoring of primes seems to be exponential. Can anyone explain how it's calculated?
For example if a gfn 21 or 22 was found tomorrow, what prime score would they have?
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My lucky numbers 10590941048576+1 and 224584605939537911+81292139*23#*n for n=0..26 | |
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For those who are interested, the formula is:
score = X^3 * ln(X) / Q
X is the size of the number expressed in base e -- i.e., it's similar to the standard length calculation LOG10(k) + LOG10(b)*n, except using the natural logarithm instead of the base 10 logarithm. So X = ln(k) + ln(b)*n.
Q is a scaling factor equal to 150732545640984000.
Furthermore, if you're the double checker, the score is reduced by 50%.
Michael posted this a while back | |
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robishVolunteer moderator
Volunteer tester
Send message
Joined: 7 Jan 12
Posts: 2136
ID: 126266
Credit: 6,782,465,899
RAC: 2,761,228
|
For those who are interested, the formula is:
score = X^3 * ln(X) / Q
X is the size of the number expressed in base e -- i.e., it's similar to the standard length calculation LOG10(k) + LOG10(b)*n, except using the natural logarithm instead of the base 10 logarithm. So X = ln(k) + ln(b)*n.
Q is a scaling factor equal to 150732545640984000.
Furthermore, if you're the double checker, the score is reduced by 50%.
Michael posted this a while back
Thanks recoil44, I must have missed it. Cheers.
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My lucky numbers 10590941048576+1 and 224584605939537911+81292139*23#*n for n=0..26 | |
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