## Other

drummers-lowrise

Message boards : General discussion : Prime Score

 Subscribe SortOldest firstNewest firstHighest rated posts first
Author Message
Message 122888 - Posted: 25 Nov 2018 | 14:03:13 UTC

The scoring of primes seems to be exponential. Can anyone explain how it's calculated?

For example if a gfn 21 or 22 was found tomorrow, what prime score would they have?

____________
My lucky numbers 10590941048576+1 and 224584605939537911+81292139*23#*n for n=0..26

Message 122890 - Posted: 25 Nov 2018 | 15:50:51 UTC - in response to Message 122888.

For those who are interested, the formula is:

score = X^3 * ln(X) / Q

X is the size of the number expressed in base e -- i.e., it's similar to the standard length calculation LOG10(k) + LOG10(b)*n, except using the natural logarithm instead of the base 10 logarithm. So X = ln(k) + ln(b)*n.

Q is a scaling factor equal to 150732545640984000.

Furthermore, if you're the double checker, the score is reduced by 50%.

Michael posted this a while back

Message 122891 - Posted: 25 Nov 2018 | 15:53:54 UTC - in response to Message 122890.

For those who are interested, the formula is:

score = X^3 * ln(X) / Q

X is the size of the number expressed in base e -- i.e., it's similar to the standard length calculation LOG10(k) + LOG10(b)*n, except using the natural logarithm instead of the base 10 logarithm. So X = ln(k) + ln(b)*n.

Q is a scaling factor equal to 150732545640984000.

Furthermore, if you're the double checker, the score is reduced by 50%.

Michael posted this a while back

Thanks recoil44, I must have missed it. Cheers.
____________
My lucky numbers 10590941048576+1 and 224584605939537911+81292139*23#*n for n=0..26

Message boards : General discussion : Prime Score