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MEGA project
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Crun-chi Volunteer tester
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Joined: 25 Nov 09 Posts: 3247 ID: 50683 Credit: 152,646,050 RAC: 18,212
                         
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At current rate port will be empty in about 60 days.
So, after that, project will be over or there will be new test available?
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RogerVolunteer developer Volunteer tester
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Joined: 27 Nov 11 Posts: 1138 ID: 120786 Credit: 268,668,824 RAC: 0
                    
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MEGA is testing some 10<k<100, N~=3.4M:
http://prpnet.mine.nu:12010/pending_tests.html
I can't see why we can't just keep testing higher N. Can't see the reservation on http://www.prothsearch.com/ though.
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Crun-chi Volunteer tester
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Joined: 25 Nov 09 Posts: 3247 ID: 50683 Credit: 152,646,050 RAC: 18,212
                         
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I dont know can we or can we not search deeper, so I ask admins to answer :)
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4 * 650^498101-1 CRUS PRIME
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Crun-chi Volunteer tester
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Joined: 25 Nov 09 Posts: 3247 ID: 50683 Credit: 152,646,050 RAC: 18,212
                         
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Can someone explain to me: when I found SR5 number , that K was immediately suspended from further crunching.
But in this range MEGA has already founded one prime, but it ( look like) will crunching to end .
So why is MEGA so different then SR5?
Thanks for reply.
____________
92*10^1585996-1 NEAR-REPDIGIT PRIME :) :) :)
4 * 650^498101-1 CRUS PRIME
2022202116^131072+1 GENERALIZED FERMAT
Proud member of team Aggie The Pew. Go Aggie! | |
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Can someone explain to me: when I found SR5 number , that K was immediately suspended from further crunching.
But in this range MEGA has already founded one prime, but it ( look like) will crunching to end .
So why is MEGA so different then SR5?
Thanks for reply.
SR5 has only one factor for specific k, MEGA can have more than one. | |
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Can someone explain to me: when I found SR5 number , that K was immediately suspended from further crunching.
But in this range MEGA has already founded one prime, but it ( look like) will crunching to end .
So why is MEGA so different then SR5?
Thanks for reply.
Read the project description:
http://www.primegrid.com/forum_thread.php?id=3008&nowrap=true#30725
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676754^262144+1 is prime | |
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Michael Goetz Volunteer moderator Project administrator
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Joined: 21 Jan 10 Posts: 14037 ID: 53948 Credit: 477,051,011 RAC: 285,770
                               
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The purpose of SR5 is to prove two conjectures.
The purpose of MEGA is to find prime numbers.
The two projects have very different goals. In SR5, we're attempting to prove the conjectures by find a prime at each of the remaining k's. If we find a prime for every k, the conjecture is proven. There's no need to find more than one prime at each k to prove the conjecture, so after a prime is found we stop searching that k since it's a waste of computer resources.
For MEGA, we're just looking for prime numbers, so there's no reason to stop searching a k because a prime was already found.
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Crun-chi Volunteer tester
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Joined: 25 Nov 09 Posts: 3247 ID: 50683 Credit: 152,646,050 RAC: 18,212
                         
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The purpose of SR5 is to prove two conjectures.
The purpose of MEGA is to find prime numbers.
The two projects have very different goals. In SR5, we're attempting to prove the conjectures by find a prime at each of the remaining k's. If we find a prime for every k, the conjecture is proven. There's no need to find more than one prime at each k to prove the conjecture, so after a prime is found we stop searching that k since it's a waste of computer resources.
For MEGA, we're just looking for prime numbers, so there's no reason to stop searching a k because a prime was already found.
So, does it mean that in every K must be one prime ( in case of SR5 and extended Sierpinski)?
This is answer I need, simple and understandable
Thanks Michael
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4 * 650^498101-1 CRUS PRIME
2022202116^131072+1 GENERALIZED FERMAT
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So, does it mean that in every K must be one prime ( in case of SR5 and extended Sierpinski)?
This is answer I need, simple and understandable
The answer is NO, there doesn't need to be one at every K, but then that proves the theory is wrong.
If there is one at every K then the theory is proved correct.
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Crun-chi Volunteer tester
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Joined: 25 Nov 09 Posts: 3247 ID: 50683 Credit: 152,646,050 RAC: 18,212
                         
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Pooh, thanks for explanation!
I ask that question since I "calculate chance of finding prime" in ESP or MEGA.
Since there is 14 left K at ESP and 3 K are eliminated ( primes are found) then I assume that chance is bigger in ESP then in MEGA.
Even if only few K have prime, and other doesnot have it, I still assume chance is bigger. And at the end of range for k on ESP , number is about 1.200.000 digits long so it will be big prime :)
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92*10^1585996-1 NEAR-REPDIGIT PRIME :) :) :)
4 * 650^498101-1 CRUS PRIME
2022202116^131072+1 GENERALIZED FERMAT
Proud member of team Aggie The Pew. Go Aggie! | |
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